Very Computer

One more question..  :)

Consider again my example class, say I had:

class Class {
        public:
                static Class foo();
                static const Class& constFoo();

Quote:}

and in foo:

static Class
Class::foo
{
        Class myvar;
        ...
        return myvar;

Quote:}

Is this *legal*?  Or would myvar also have to be declared static?
I'm assuming it is *not* because wouldn't myvar be placed on the runtime
stack, and then when the function ends, all of its contents from the
runtime stack are deleted?  Or is this a special case because foo
itself is static, so it will not necessarily run on the runtime stack?

And what about:

static const Class &
Class::constFoo() {
        Class myconstvar;
        ...
        return myconstvar;

Quote:}

Will I be able to return a pointer to a private variable of a static
class?  

Tks,
Patrick

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Lose the 'static' keyword here.  THAT'S illegal.

Quote:> Class::foo
> {
> Class myvar;
> ...
> return myvar;
> }

> Is this *legal*?  Or would myvar also have to be declared static?

No.  That's fine.  You're returning an object which will be created
when the function is about to return control to its caller.

Quote:> I'm assuming it is *not* because wouldn't myvar be placed on the runtime
> stack, and then when the function ends, all of its contents from the
> runtime stack are deleted?  Or is this a special case because foo
> itself is static, so it will not necessarily run on the runtime stack?

No, it has nothing to do with Class::foo being static.  It is so
called "returning by value".  Read about it in your favourite C++
book.

Quote:

> And what about:

> static const Class &

Again, lose the 'static' keyword here.

Quote:> Class::constFoo() {
> Class myconstvar;
> ...
> return myconstvar;
> }

> Will I be able to return a pointer to a private variable of a static
> class?

First, that's not a pointer, that's a _reference_.  And, no, you
will not be able.  Read FAQ, section 8.  Or your favourite C++
book.  They usually talk about returning a reference to a local
variable.

Victor
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Why is it illegal here?  (I've just written some code where I have
a static functon in a class definitoin (in the .h file) and it
compiles fine).

Thanks,
Patrick

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class HasStaticMember
{
    static void foo();  // declaration of a static member - OK

Quote:};

static void HasStaticMember::foo() // definition -- not OK
{

Quote:}

You had the definition outside the class.  That's why I said
"lose the static keyword".

Victor
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Victor,

Ahh, I see.  Yes, found the error in that.  Now, looking for
solutions.  Pls see my other news article.

Thanks for your help so far,
Patrick.

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