Very Computer

If I have a Xpath in a variable

<xsl:variable name="mypath">/data/mynane</xsl:variable>

How do I than use this to select the data

<xsl:value-of select="??($mypath)"/>

I've written a java function for the ?? above but the call out to java
is slow so large pages a 10* slower than a simple transform.

No way without extension function.
Why do you need it?
What's wrong with usual

<xsl:variable name="mydata" select="/data/mynane"/>
...
<xsl:value-of select="$mydata"/>

--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel

I've posted a "Spooky Magic" message with a full example.

In summary the XPATH that we want is defined in an XML document (along
with the page content - i.e. the words aroung the data):

 <bdata src="/mydata/myname"/>

and the template "bdata" does

 <xsl:value-of select="get_node($src)"/>
 (I know this could be one step)

and my java

<msxsl:script language="JScript" implements-prefix="cache">
<![CDATA[
function get_node(srcValue)
{      
return srcValue.item(0).selectNodes(srcValue.item(0).text);

Quote:}

]]>
</msxsl:script>

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That's quite unusual case, when data also contains XPath expressions. And
usual approach for this unusual case is two-step transformation, when first
you are generating xslt stylesheet on the fly and then run it.
--
Oleg Tkachenko
http://www.tkachenko.com/blog
Multiconn Technologies, Israel