Very Computer

thank you

| I have an application that creates data on another platform than Linux
| and when we read these datas on the linux box, we have to work on the
| order of the bytes by eight block count. Is there a mean to do the work
| automatically by options on the opening of the file ? where can i find
| answers on this subject ?

If the application on the Linux box is one you can change the code for
(such as you wrote it yourself) then simply read the data in the byte
order you know it to be.

I don't know what you mean by "the order of the bytes by eight block count".
But if you know when in the input stream you have one of these integers
and how many bytes it is, then just read it one byte at a time and shift
it into an integer variable in the appropriate order.  If you are reading
a number in big endian, then you start by having a variable assigned with
the value 0, and for each byte read in, shift it left by 8 bits and add
in the new one.  If the number is little endian, you pre-shift the byte
by N times 8 bits where N is the byte count sequence starting with 0,
and add that to the accumulation variable.  The resultant code will be
a little slower, but will be portable (e.g. it will read the data in the
fixed byte order regardless of the byte order of the host running it).

There are also some tools around to do this that better optimize cases
where the re-ordering isn't needed.  You could use the network byte
order functions in the socket library if your data fits that scheme.

--
| Phil Howard - KA9WGN | My current websites: linuxhomepage.com, ham.org
| phil  (at)  ipal.net +----------------------------------------------------

Quote:>I have an application that creates data on another platform than Linux
>and when we read these datas on the linux box, we have to work on the
>order of the bytes by eight block count. Is there a mean to do the work
>automatically by options on the opening of the file ? where can i find
>answers on this subject ?

>thank you

(2) What does "order of the bytes by eight block count" mean?

(3) Generally speaking, reversing endian-ness has to be done by
individual programs. While it is true that X servers cater for
different endianness of the client computer, other programs seem not
to do so. So you are probably on you own in this. However, here is a
procedure to reverse endianness of integers:-

PROC reverse endianness = (INT n)INT:
BEGIN
   INT
      bits per byte = 8,
      bytes per int = 4;
   BITS bn=BIN n;  #Convert to a mode where bits are accessible#
   BITS result:=2r0; #Set to zero#
   FOR i TO bytes per int
   DO
      BITS isolate byte=bn SHR bits per byte*(i-1) AND 16rff;
      result:=result OR isolate byte SHL bits per byte*(4-i)
   OD;
   ABS result
END; #reverse endianness#

A compiler for the above routine may be had merely by downloading the
file mentioned in my sig.
--
Sian Leitch (Software Engineer specialising in Algol 68)
Algol 68 for Linux is available from me or at
<ftp://vestein.arb-phys.uni-dortmund.de/pub>
Look for ctrans_0.1.0.tar.gz

Way back when, Mark Williams Co. used to sell a v7 clone called
Coherent which ran on various processors (8086, 68K, etc.).
They had a patent on storing data on disk in a standard byte
order.  So, if you write data to disk in network order you owe
them royalties -- perhaps it's expired.  I don't know that they
ever tried to enforce it, and MWC is, I believe, out of
business anyway.

--
Grant Edwards                   grante             Yow!  YOW!!! I am having
                                  at               fun!!!
                               visi.com            

--