Very Computer

1. Variable substitution within a variable name

Anyone know of a way to use embedded variable names?

i am trying to setup a shell menu for a user to be able to choose a
printer based on their location.  Since their are different numbers of
printers at each location, i am trying to make it dynamic, not static.
I have tried many combinations to no avail so far.

The test script below gets a dynamic list of printers for a particular
store, then should present a menu of those printers for the user to
select. in this case, there are 4 printers so the menu displayed
should be, for example:

1 for printer store032a
2 for printer store032b
3 for printer store032c
4 for printer store032d

Not quite what I am getting.

i=1
lpstat -a | grep store032 | awk '{ print $1 }' |
while read prn
do
   out{$i}=`echo ${prn}`
   echo "$i for printer ${out${i}}"
   i=`expr $i + 1`
done  

Result of running the above script:
printer_names.sh: out1=store032a: not found
printer_names.sh: bad substitution

Anyone have a way to do this, preferably in the bourne shell?

Thanks
--
Robert A. Johnson
Systems Administrator
Cost-U-Less Inc.
8160 304th Ave. SE
Bld. 3 Suite A
Preston, WA 98050
425-222-5022 #161
425-417-2591 (cell)

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