by Paul Porcel » Sat, 09 Sep 1995 04:00:00
i now have the following loop
for i in 3
do
echo $jbc$i
done
What i actually want to print is the value 8.
i.e. substutute the $i for 3 , then evaluate $jbc3.
Is there some way to combine these two substitutions.
Thanks in advance.
--
Paul Porcelli
Dept of Aerospace Engineering
University of Glasgow
by Andreas Schw » Sat, 09 Sep 1995 04:00:00
|> I have two variables
|> jbc3=8
|> i=3
|> i now have the following loop
|> for i in 3
|> do
|> echo $jbc$i
|> done
|> What i actually want to print is the value 8.
|> i.e. substutute the $i for 3 , then evaluate $jbc3.
|> Is there some way to combine these two substitutions.
eval echo \$jbc$i
--
Andreas Schwab "And now for something
by Zefr » Sun, 10 Sep 1995 04:00:00
>for i in 3
>do
> echo $jbc$i
>done
-zefram
1. Command Substitution within Parameter Substitution?
Hi,
(GNU bash, version 2.05b.0(1)-release (i586-mandrake-linux-gnu).)
Is it possible, in the above version of BASH, to have (a) command
substitution(s) within (a) parameter substitution(s)? I tried the
following in a BASH script:
gqview ${$( cat $HOME/mydisplay_return )#*\ }
and it didn't work. The above code line was to execute GQview (an image
viewer) with the name of an image file that was stored, on it's own, in a
file called 'mydisplay_return', hence the 'cat' command to get at the image
file name. The file name stored in the 'mydisplay_return' file was
prefixed with an identifying number followed by a space, hence the '#*\ '
parameter substitution to just leave the file name. But it doesn't work.
What's wrong?
Yours,
Gary Hayward.
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