Very Computer

I've looked in this group for an FAQ hoping to find something to use but
to no avail. I'm on BSD Unix using csh as my shell. I have a directory of
numerous files that get updated frequently and I'd like to copy only
those files matching a command-line argument (such as "Apr 27") to
another directory.

This seems like such a trivial task, and I'm close to a solution, but
it's not quite working.

I've approached it from 2 directions. I don't care which one the solution
addresses. I just need *help* :-)

1) I can get a list of filenames quite easily using the following script:

#!/bin/csh -f
ls -l ~/myhtml/*.html | grep "$1" >! today.list
cut -c68-90 today.list >! names.list
cat names.list

However, this presents me with the problem of looping through this file
and processing each line. I don't know enough about awk, perl, or sed to
do this.

2) The other attempt is a shell script as follows:

#! /bin/csh
# update version 6
# Copy files matching command line argument (usually date).

foreach file (`ls -l ~/myhtml/*.html | grep $1`)
 cp $file ~/in/
 cp $file ~/public_html/
end

This doesn't work. If anyone can help I would *really* appreciate it.
Email direct would be preferable. Thanks in advance and bcnu...

--
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Quote:>#!/bin/csh -f
>ls -l ~/myhtml/*.html | grep "$1" >! today.list
>cut -c68-90 today.list >! names.list
>cat names.list

>However, this presents me with the problem of looping through this file
>and processing each line. I don't know enough about awk, perl, or sed to
>do this.

>2) The other attempt is a shell script as follows:

>#! /bin/csh
># update version 6
># Copy files matching command line argument (usually date).

>foreach file (`ls -l ~/myhtml/*.html | grep $1`)
> cp $file ~/in/
> cp $file ~/public_html/
>end

>This doesn't work. If anyone can help I would *really* appreciate it.
>Email direct would be preferable. Thanks in advance and bcnu...

--

"Even the samurais have teddy bears, and even the teddy bears get drunk"
(don't ask me what it means, it came from the 'fortune' program).

: I've looked in this group for an FAQ hoping to find something to use but
: to no avail. I'm on BSD Unix using csh as my shell. I have a directory of
: numerous files that get updated frequently and I'd like to copy only
: those files matching a command-line argument (such as "Apr 27") to
: another directory.

[...]

: foreach file (`ls -l ~/myhtml/*.html | grep $1`)
                                              ^^
                                        try grep "$1" instead.

--

          St.Strelnik

Down with categorical imperative!

But your whole task could be done in one line: cp  *'Apr 27'*  newdir

When you use a script and pass it an argument containing a space, you
do need to always quote that space on the command line, e.g., Apr\ 27
or 'Apr 27', as well as referencing it in double quotes in the script.
--

1st: Have a look at the find command. You can search for files that
        are touched since a specified time/date or that are newer
        than an other file. If you only have the 'newer than file'
        option, end your job touching a timestamp file.
        The next works if  has no subdirectories.
find /source/dir -newer /TmStDir/TimeStampFile -exec cp {} /target/dir/`basename {}` \; ; touch
/TmStDir/TimeStampFile

2nd: If the number of files and the filenames are verry constant and
        they are only updated, you could make a `makefile`.
% cat makefile
/target/dir/file1:      /source/dir/file1
        cp /source/dir/file1 target/dir/file1
/target/dir/file2:      /source/dir/file
        cp /source/dir/file2 target/dir/file2
/target/dir/file2:      /source/dir/file2
        cp /source/dir/file2 target/dir/file2

and execute this in the directory with the makefile with:
% make

The first option will copy all files which are newer, including the realy new files
The second option will only copy the files you specify.

Groetjes en succes
Corne

--
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