Very Computer

Hi,

I would like to know how I can pass double quotes to a perl script in
a csh or sh in UNIX. ie
I have a test script which has:
#!/usr/local/bin/perl5
print "arg0\n";

print "\narg1\n";

print "\narg2\n";

print "\n";

and I say:
./test  hello  "1 2"
arg0
hello
arg1
1 2
arg2

I would like arg1 to be "1 2" and not just 1 2
It looks like the " are being stripped out of the argument by the
parser. Similarly, I would like:
./test  hello  '1 2'
arg0
hello
arg1
1 2
arg2

to print '1 2' for arg1.

the reason I need this is because I am passing "1 2" to another script
which requires these arguments to have "" around them. If the " is
missing, it only reads 1 instead of 1 2
IT is transparent to the user that this is a wrapper they are
executing and so I wnt to avoid doing things like \"1 2\" when passing
arguments.

Thanks in advance for any help,

Sam

These are syntax errors. The first argument is $ARGV[0]. It's a good
idea to always

use warnings;
use strict;

in perl scripts (although that's not your problem here).

Quote:> and I say:
> ./test  hello  "1 2"
> arg0
> hello
> arg1
> 1 2
> arg2

> I would like arg1 to be "1 2" and not just 1 2

> It looks like the " are being stripped out of the argument by the
> parser.

Well, they're being stripped off by the shell. If you want quotes
around stuff that you emit from the perl script, you'll have to either
know what needs to be quoted, and add the quotes before you emit the
output, or quote everything when you output it. The latter is no doubt
easier, and won't bother the downstream script.

Joe
--
Everyone in this room is wearing a uniform, and don't kid yourself.
   - Frank Zappa