Very Computer

Thanks

if [ X$(echo $SOMEVAR|tr -d "[0-9]")  = X ]
then
    echo "\$SOMEVAR is numeric or undefined"
else
    echo "\$SOMEVAR is not numeric"
fi

should do the trick, assuming SOMERVAR has been defined and is not an empty
string, though I haven't tested this.

Ta

Ta

  [[  "$1"  =  +([0-9])  ]]

cheers,
gary

--
Chris

I just need it to verify a integer value, no + or - or anything else to worry
about.

If anyone else has some other need way please pass it along.

Thanks

Which numeric formats did you have in mind?  

This is not a trivial question.  :-)

Chuck Demas
Needham, Mass.

--
  Eat Healthy    |   _ _   | Nothing would be done at all,

  Die Anyway     |    v    | That no one could find fault with it.

case $var in
   *[!0-9]*) # non-numeric;;
   '') # empty string;;
   *) # numeric;;
esac

This is portable for all bournish shells.  Shells that support
extended globbing like ksh and bash 2 can use the following syntax:

    if [[ $var = +([0-9]) ]];then echo integer;...

You need to turn on extended globbing in bash with shopt:

   shopt -s extglob

--
Dan Mercer

Opinions expressed herein are my own and may not represent those of my employer.

# isnum returns True if its argument is a valid number.
# The first pattern requires a digit before the decimal
# point, and the second after the decimal point.
# bsh: does not acount for: 0e0 (no decimal point)

case $1 in
 (?([-+])+([0-9])?(.)*([0-9])?([Ee]?([-+])+([0-9])))
        return 0 ;;
 (?([-+])*([0-9])?(.)+([0-9])?([Ee]?([-+])+([0-9])))
        return 0 ;;
 *)     return 1 ;;
esac

-Brian