Very Computer

Hi,

I would like  to  get rid of the occurences of ^M^J charachter combination
(carriage return & line feed combination)in my file.
That is I want to get rid of  all  the  occurences of   \015\012

For Example, the following file

1234^M
456
^M
789

should becom

123456
789

Any help is greatly appreciated.
Thanks in advance,,,,,Murty

tr -d '\015' < FILE > NEWFILE

This gets rid off all ^M characters in the file; if you want to keep those
that are not at the end of a line, check the archives; this was discussed
recently: http://groups.google.com/groups?hl=en&group=comp.unix.shell

--
    Chris F.A. Johnson                        http://cfaj.freeshell.org
    ===================================================================
    My code (if any) in this post is copyright 2001, Chris F.A. Johnson
    and may be copied under the terms of the GNU General Public License

CTRL_M=`printf '\r'`
sed -e '
  :1
  /'"$CTRL_M"'$/{
    s///
    $!N
    s/\n//
    t1
  }'

It will also remove a trailing ^M on the last line. So, if your file
ends with '^M^J', it will be OK, if your file ends with '^M', either
your sed really doesn't like it and it will delete this line, either
your sed can handle it and the trailing ^M will be removed. But a text
file is supposed to end with ^J.

--
Stphane

use tr, 'man tr'

to delete characters use the '-d' switch;

tr -d '\15\12' <sourcefilename >destinationfilename

that will put the whole file all together in one line.
the line should at least be terminated with a single LF;

echo >>destinationfilename

if you just want to remove the CR characters (to get
a UNIX compatible text file with no ^M's showing up);

tr -d '\15' <sourcefilename >destinationfilename

BTW: I have a port of BSD 'tr' for MSDOS available on my
     website. See the TOOLS page.

byefrom

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