Very Computer

Hello all!

This should be really simple, but for some reason the solution evades me.  
Consider this:

#!/bin/bash
my_var = '/home/nikita/foo.txt'
echo $my_var

This will print

/home/nikita/foo.txt, of course.  I want it to print just "foo.txt"--I want
to strip out the pathname info.  How do I do it in BASH?  

TIA.

Nikita.

my_var='/home/nikita/foo.txt'
echo ${my_var##*/}

        Ed.

  No, you'll get an error message:

bash: my_var: command not found

Quote:>  I want it to print just "foo.txt"--I want
> to strip out the pathname info.  How do I do it in BASH?  

my_var=/home/nikita/foo.txt
echo ${my_var##*/}  

--
    Chris F.A. Johnson                        http://cfaj.freeshell.org
    ===================================================================
    My code (if any) in this post is copyright 2003, Chris F.A. Johnson
    and may be copied under the terms of the GNU General Public License

Quote:>Hello all!

>This should be really simple, but for some reason the solution evades me.  
>Consider this:

>#!/bin/bash
>my_var = '/home/nikita/foo.txt'
>echo $my_var

>This will print

>/home/nikita/foo.txt, of course.  I want it to print just "foo.txt"--I want
>to strip out the pathname info.  How do I do it in BASH?  

>TIA.

>Nikita.

man basename

or

echo $my_var sed 's:.*/::'

Chuck Demas

--
  Eat Healthy        |   _ _   | Nothing would be done at all,

  Die Anyway         |    v    | That no one could find fault with it.

Quote:>> #!/bin/bash
>> my_var = '/home/nikita/foo.txt'
>> echo $my_var

>> This will print

>> /home/nikita/foo.txt, of course.
>   No, you'll get an error message:

> bash: my_var: command not found

Of course it will.  Spaces are my downfall--a carry-over habit from C++.

Quote:>>  I want it to print just "foo.txt"--I want
>> to strip out the pathname info.  How do I do it in BASH?  

> my_var=/home/nikita/foo.txt
> echo ${my_var##*/}  

Thanks a lot.  I knew the solution was a few characters long, but just
couldn't figure it out.

Nikita.