Very Computer

Hi,

I'm trying to use ls with a negative form of wildcard, e.i. I want to list
all files that so not have a certain ending. Is there a way of doing this?

Thomas Mitchell

On 11 Dec 2002 13:22:45 GMT

Are you looking for something like
$ ls *[^html]
or
$ ls | grep '*[^html]'
,or something more complex?

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In article

[...]

Quote:> $ ls *[^html]

In a Bourne shell or with some kshs, this will return the list
of filenames that end with either ^, h, t, m or l.

With bash, zsh and some other shells, this will return the list
of filenames that end with neither of the h, t, m, or l
characters.

(excluding dot files)

Quote:> or
> $ ls | grep '*[^html]'

Will return the list of filenames (or only some lines of them)
that contain '*' followed by any character different from h, t,
m or l.

This question was asked few days ago (and many times before) in
comp.unix.shell.

--
Stphane

As far as I know, there's no way to do this with standard globs, though
you could get the same effect in conjunction with, say, grep -v.

zsh and other shells have extended glob options when enabled which allow
you to do things like

        ls ^*.html

or

        ls *~*.html

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