by Tim Partridg » Sat, 06 Jul 2002 03:23:26
:%s/A/ A /g
How can I achieve the same effect if I don't explicitly know what character
to replace? Thanks!
by John W. Krah » Sat, 06 Jul 2002 04:56:51
> I don't know regular expressions like the back of my hand yet, but I'm
> working on it :) Can someone tell me how to replace a matched pattern with
> itself and some extra characters? For example, I want to replace all
> instances of [A-Z] with the same thing, but with a spaces around it. So if I
> only had "A"s in my text, in vi I could write
> :%s/A/ A /g
> How can I achieve the same effect if I don't explicitly know what character
> to replace? Thanks!
John
--
use Perl;
program
fulfillment
by Dave Near » Sat, 06 Jul 2002 19:06:37
In sed:Quote:> I don't know regular expressions like the back of my hand yet, but I'm
> working on it :) Can someone tell me how to replace a matched pattern with
> itself and some extra characters?
For example, to replace bana with banana, you could do this...
sed -e 's/\(bana\)/\1na/g'
or this...
sed -e 's/\(ba\(na\)\)/\1\2/g'
Dave.
--
David Neary,
E-Mail: bolsh at gimp dot org
CV: http://www.redbrick.dcu.ie/~bolsh/CV/CV.html
by Barry Margoli » Sun, 07 Jul 2002 01:04:52
>:%s/A/ A /g
>How can I achieve the same effect if I don't explicitly know what character
>to replace? Thanks!
'&' in a replacement stands for whatever was matched by the pattern.
--
Genuity, Woburn, MA
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