Very Computer

1. find vs. $FIND, perhaps subshell problem

I have the following script:

#!/usr/bin/ksh
REGEXP=$1
FILE=$2
FIND_C="find . -follow -name '*.c' -exec egrep -i '$REGEXP' /dev/null {} \;"
#Works
find . -follow -name '*.c' -exec egrep -i "$REGEXP" /dev/null {} \; > $FILE
# Does not work
$FIND_C > $FILE
#Works
eval $FIND_C ">" $FILE

Okay, now if I take the file redirection out, the results above still hold:
find ...     #works -->regexp found
$FIND_C      #fails -->quietly works, but with no results
eval $FIND_C #works -->regexp found

Assuming that I'm not doing anything stupid 8)... why does the second
one fail?

I'm wondering if there is some subtle interaction going on between
subshells, or maybe in the second one, the shell doesn't interpret
$FIND_C twice like it would in eval?

that is in the eval line, the current shell interprets $FIND_C, then
eval interprets the interpretation in a subshell.  Is that right?

thanks again.

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