Very Computer

What I want to do is to split up an argument passed to a
bash-shellscript. I want to run the script like this:

<scriptname> arg1 arg2 arg3 <...>

With an *unknown* amount of arguments.
This is what my script looks like:

#!/bin/sh
# I want to echo all the parameters I pass this script. One after the other.

declare -i i=1
while [ $i -le $# ]
do
  echo <what shall I put here ?>
  i=i+1
done

echo $i counts from 1 to the number of arguments. How do I make it
echo the arguments one after the other ?

                        TNX Andreas

PS: Email would be appreciated.

-----------------------------------------------------------------------------

                                              Andreas Steffan

* win: command not found

------------------------------------------------------------------------------

        NUMARG=$#
        until [ $[NUMARG] -le 0 ] ; do
                echo $1
                NUMARG=$[$[NUMARG]-1]
                if [ $[NUMARG] -gt 0 ] ; then shift ; fi
        done

The "shift" command "down-shifts" the arguments: $1 is now set to what
$2 was, $2 is now what $3 was, and the original $1 has dropped off the
face of the earth.

The "$[..]" means to evaluate numerically.

E. A. Graham, Jr.
Unemployed Computer Geek
(Remainder of .sig censored by the CDA provisions in the Telecomm
Bill...)

: <scriptname> arg1 arg2 arg3 <...>

: With an *unknown* amount of arguments.
: This is what my script looks like:

: #!/bin/sh
: # I want to echo all the parameters I pass this script. One after the other.

: declare -i i=1
: while [ $i -le $# ]
: do
:   echo <what shall I put here ?>
:   i=i+1
: done

try

   do
      echo $ARGUMENT
   done

--

do
   echo $x
done
Andrew Snyder

char disclaimer[] = {'\0'}; /* I'm on cash net */