in bash shell
(my idea is redirect them to a tmp file first, and then read from it...)
works, but is stupid... any one could lend me a hand?
thx in advance
Mandrake C.
by Mandrak » Thu, 22 Nov 2001 16:53:57
Mandrake C.
by Dave Bro » Fri, 23 Nov 2001 05:02:31
date_out=$(date) -or- date_out=`date` #note: "`" = backtick, not apostrophe
You might get a hold of a shell programming book, or do a google search
for "bash tutorial". bash is about 95% compatible with korn shell, so
a ksh book would be a reasonable substitute.
--
Dave Brown Austin, TX
1. Redirect output using a shell variable??
I am writing a ksh script in which I want to give the user the option to
see the output of the commands the script executes. I've never tried to
do this before (though I've written a fair number of ksh scripts), and
my first thought was to do something like this:
# show output by default
REDIR=
# if we saw the "hide output" command-line flag, hide it
if [ "$HIDE_OUTPUT" ]
then
REDIR=" > /dev/null 2>&1"
fi
# execute the command /path/foo
/path/foo $REDIR
However, ksh (and the Bourne shell, too) seems to execute /path/foo
(whatever it happens to be) using " > /dev/null 2>&1" as arguments to
the command rather than expanding the variable prior to execution.
For example, here's what I see in an interactive shell with ls:
$ temp=" > /dev/null 2>&1"
$ echo $temp
$ echo ls $temp
ls > /dev/null 2>&1
$ ls $temp
2>&1: No such file or directory
/dev/null
$
Can someone explain this behavior to me, and possibly suggest a solution
to my problem (I'd like to avoid the messiness of "if [ "$HIDE_OUTPUT" ]
then; /path/foo > /dev/null 2>&1; else /path/foo; fi" if at all
possible, since there are many places I want to use this)? Thanks for
any help...
Ernie Pistor
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