Very Computer

# touch -m 02260000 /tmp/file1
# touch -m -t 02262359.59 /tmp/file2
# find <dir> -newer /tmp/file1 ! -newer /tmp/file2 -ls

Other options would be to...
1) Write a small script in perl.  This would potentially allow you to
   parse the date you give to it, and would not require temporary files.
2) Parse the find output of all files for the date.  Something like...

# find <dir> -ls | grep "26 Feb"

--

Unix System Administrator                    Taos - The SysAdmin Company
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#!/bin/ksh
integer date=$(date +%j)
integer target_date=$(date -d "${1:-today}" +%j)
exec find -daystart -mtime $((date-target_date))

This takes a suitably quoted target date (e.g. '26 Feb') as its only
argument. You'll need to modify it to handle previous years' dates, or
further options, tests, etc. for find. Of course, if you can work out the
difference yourself, you can just type:

find -daystart -mtime 44 (or whatever)

HTH

Matt M

Quote:> How do I use "find" to print out filenames (including paths) of files with
a
> date I specify?  e.g. I want to show all files on my server that have a
date
> of "26 Feb".