Very Computer

However while shell script perform "some_jobs", it received
repeated Control-C, what is going to happen? How can I
ignore the repeated Control-C and finish the jobs. Thanks.
--
unix programs: niftp (non-interactive recursive ftp), hide (hide command args),
submit (replace nohup), etc from ftp://ftp.mindspring.com/users/mwang/unix-prog

If I have not misunderstood your question you are trying to catch "ctrl-c" and
"ctrl-z" signals. Usually the system call "signal" was used but this is the old
method for
catching signals. Now is best-used the system call sigaction to perform this
operation.

Here is the code of a small program catching the signal SIGINT (ctrl-c). The
program
counts down from 10 to 1 and every time the ctrl-c is pressed, the signal is
catched and
and a warning message is printed out. Here is the code:

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <signal.h>

main () {
  void sigint_handler (int signo);

  int i;
  struct sigaction sa;
  char s[100];
  sigset_t mask;

  sigemptyset(&mask);
  sa.sa_handler = sigint_handler;
  sa.sa_mask = mask;
  sa.sa_flags = SA_RESTART;
  sigaction(SIGINT, &sa, NULL);  // you should error-check this line.

  for (i = 10; i >= 1;i--) {
     printf("%d\n", i);
     sleep(1);
  }

Quote:}

Quote:}

Best regards,

Oscar Morales.

some_jobs ( )
{
    trap "" 1 2 3 15

    # then do whatever ...

    # and perhaps exit from here ...
    exit 1

Quote:}

Best regards,

Lawson Hanson