1. How to find nos. of cyl in HD ?
I am absolutely new to Linux. Infact, I haven't even installed it on my PC yet,
though, I've acquired all the necessary FAQs & HOWTOs and the Slackware (3.0).
While going thru the partitioning of HD using FIPS, I'm not able to figure out
the cylinders start,end for my different partitions. I have a Cyrix P66+ with
16MB RAM, 2.1GB IDE HD with WINDOWS95 on it and I am trying to have the
partitions as follows:
Partition_1 100 MB for Linux native / (root partition)
Partition_2 1.1 GB for DOS
Partition_3 30 MB for Linux swap
Partition_4 870 MB for Linux native /usr
I understand that Linux root partition must start below 1024 or else
it will not boot thru LILO (is it OK to have it right in the beginning ?).
Now, how do I know how many cylinders are there in this HD ? The
"CMOS SETUP UTILITY" (pressing DEL during DOS boot up) displays :
Options Size Cyls Head Precomp Landz Sector Mode
2(Y) 2112 1023 64 0 4091 63 LBA
1 2112 4092 16 65535 4091 63 Normal
3 2112 2046 32 65535 4091 63 Large
Is it correct to assume that all the three are same with
different formats ('cos Cyls*Heads=65472 for all). If so, then
which is the correct nos. of cylinders for my HD ?
I'm not sure how but I have a feeling that my HD has 4092 cylinders
(since DOS can't handle more that 1024, we don't see them)and if this
is correct, then is it correct to have following four primary
partition Begin Start End Type
1 1 1 200 Linux native / (100MB)
2 201 201 2400 DOS (1.1 GB)
3 2401 2401 2460 Linux swap (30MB)
4 2461 2461 4092 Linux native /usr (870MB)
Is it do_able thru FIPS ? I did try running FIPS and got the
following display but could not proceed much as I didn't know what
to make out of it.
Old partition cylinder New partition
803.2MB 408 1208.8MB
Since my HD is 2.1GB, these numbers did not make much sense to me.
(I thought my HD was a single partition, all of which was being used
in primary partition_1 for DOS+Windows95 !!)
I am sure this problem has already been addressed before but I'd really
appreciate if someone cud repeat the solution.
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