Very Computer

Hi all,
   I want to get all interfaces address infomations with
gethostent(3)(NOT with gethostbyname of getaddrinfo).And i use the
Ubuntu10.10,the ipv6 is enabled by default.However,with my code
below,only the ipv4 addresses were returned,really confused :-)
will anyone give me a explanation?Thanks ahead.
code here:
#include "unp.h"

int main()
{

        struct hostent          *he;
        char                    **sa;
        char                    **alias;
        char                    buf[BUFSIZ];

        while((he = gethostent())){
                if(he == NULL){
                        perror("gethostent");
                        return -1;
                }
                printf("PROTOCOL: %s\n",he->h_addrtype == AF_INET?\
                                                "AF_INET":"AF_INET6");      
                printf("canonical name:%s\n",he->h_name);
                alias = he->h_aliases;
                for(;*alias != NULL;alias++)
                        printf("alias: %s\n",*alias);

                sa = he->h_addr_list;
                for(;*sa != NULL;sa++)
                        printf("address         %s\n",inet_ntop(he->h_addrtype,*sa,\
                        buf,sizeof(buf)));
        }
        endhostent();
        return EXIT_SUCCESS;

Quote:}

Did you read the manual?  In the Linux man page gethostent(3) is barely
mentioned, "does not make much sense", "may be available only when the
library was built without DNS support" and "will ignore ipv6 entries".

Which seems to be a way of saying "we don't believe in providing name
resolvers which only use /etc/hosts".

/Jorgen

--

\X/     snipabacken.se>   O  o   .

gethostent() gives you the contents of the hosts database (usually
/etc/hosts), not interface addresses.

It's essentially useless and has been for the last quarter century.

--
http://www.greenend.org.uk/rjk/

thanks.I didn't noticed that.