> >188.8.131.52 0.0.0.0 255.255.240.0 eth0
> >0.0.0.0 184.108.40.206 0.0.0.0 ^^^ eth0
> >> ^^^
> >It seems to me, that with this subnet mask, the 220.127.116.11 ip would
> >be a valid host ip with above subnet.
> Nope, that's perfectly fine. The network spans from
> 18.104.22.168 to 22.214.171.124.
> That doesn't mean, however, that this routing information is
> What does "ifconfig" say about your NICs settings?
> Lumber Cartel Unit #456 (TINLC) & Official Netscum
> Note: If you want me to send you email, don't munge your address.
I beg to differ sir. the way I see it is as follows:
address 126.96.36.199 (a class B) without subnetting has a network address
Default subnet mask is 255.255.0.0
inserting subnet mask of 255.255.240.0 to the 188.8.131.52 network results
in valid subnets
184.108.40.206 220.127.116.11 would be the last valid host id
with this subnet scheme.
18.104.22.168 (and 22.214.171.124 etc.) would not be a valid address in such
lastly, a 255.255.240.0 netmask on a class B network provides for 4094 hosts
This seems illogical on a cable modem network, as they typically function as
an IEEE 802.3 CSMA/CD Ethernet, such a large number of hosts would make for
a massive collision domain (without many switches, bridges, routers etc.)
and thus would have poor, if any useable bandwidth.